hi
i'm having a little trouble understanding the half equations for the electrolysis of water:
from the table of standard potenstials the two equations involving water are:
02 + 4H+ +4e- --> 2H2O (E0 = 1.23V)
2H2O + 2e- --> H2 + 2OH- (E0 = -0.83V)
for the half equations i was always told that the most positive (ie 1.23V) equation stayed the same and the other one reversed and changed signs....so this should then become:
02 + 4H+ +4e- --> 2H2O (E0 = 1.23V)
H2 + 2OH- --> 2H2O + 2e- (E0 = 0.83)
but every text book i own and all the websites i've searched have it the other way around....why?
any help would be appreciated
i'm having a little trouble understanding the half equations for the electrolysis of water:
from the table of standard potenstials the two equations involving water are:
02 + 4H+ +4e- --> 2H2O (E0 = 1.23V)
2H2O + 2e- --> H2 + 2OH- (E0 = -0.83V)
for the half equations i was always told that the most positive (ie 1.23V) equation stayed the same and the other one reversed and changed signs....so this should then become:
02 + 4H+ +4e- --> 2H2O (E0 = 1.23V)
H2 + 2OH- --> 2H2O + 2e- (E0 = 0.83)
but every text book i own and all the websites i've searched have it the other way around....why?
any help would be appreciated