thanks...i think thats what it is....can someone clarify this?minijumbuk said:Umm, I think it's only aqueous and gas.
2007 Industrial chemistry section. There was solid in the equilibrium. You just have to ignore it in the equilibrium expression.Undermyskin said:It's correct, I think. I've never dealt with a K questions that have solid in it, to my ignorance, I suppose.
But revising what we need to do, I can prove it.
What we need to calculate K are the []s of chemicals involved. These can only be applied to aqueous solutions or gases only, right? Have you ever had a concentration of any solids? This is because the 'concentration' of a solid is preserved all the time. Taking a crystal of salt as an example. The number of molecules of NaCl/ the volume that crystal occupies = constant, yeah? Because even if adding more salt into an already concentrated solution, the extra settles to the bottom, joining the solid particles. And since the density of solid salt is the same at certain temperature and pressure, 'the concentration' is also the same. The more salt you add, the larger volume it occupies with the more molecules in there.
...because they have extremely high concentration which would make your K useless, if you included it.tommykins said:Solids are ignored, along with pure liquids (l)
yeah i cbf'd writing out the reasoning. lol.Trebla said:...because they have extremely high concentration which would make your K useless, if you included it.
Yea that makes sense.... thanks everyoneUndermyskin said:It's correct, I think. I've never dealt with a K questions that have solid in it, to my ignorance, I suppose.
But revising what we need to do, I can prove it.
What we need to calculate K are the []s of chemicals involved. These can only be applied to aqueous solutions or gases only, right? Have you ever had a concentration of any solids? This is because the 'concentration' of a solid is preserved all the time. Taking a crystal of salt as an example. The number of molecules of NaCl/ the volume that crystal occupies = constant, yeah? Because even if adding more salt into an already concentrated solution, the extra settles to the bottom, joining the solid particles. And since the density of solid salt is the same at certain temperature and pressure, 'the concentration' is also the same. The more salt you add, the larger volume it occupies with the more molecules in there.
No, fail.Units depends on the K expression
units for [] is mol/L
but if it is []^2, then the units are squared as well (mol/L)^2
and so on.......
LOL mate this was ages ago.No, fail.
The K value is the ratio of products to reactants in an equilibrium system. OBVIOUSLY NO UNITS.