shinigami66
New Member
- Joined
- Sep 15, 2008
- Messages
- 20
- Gender
- Male
- HSC
- 2009
Okay the question goes
Phenolphthalein indicator turns pink in the presence of OH- ions. Consider a simple galvanic cell in which the two electrodes are zinc and iron, immersed into a saltwater electrolyte containing phenolphthalein...
a) at which electrode will the electrolyte turn pink? (i said Fe and its correct)
b)write the half-equations occurring at the cathode and anode.
so this is where i don't get, the answers says:
Cathode : 2H2O + 2e -> 2OH- + H2
Anode : Zn -> Zn2+ + 2e
when i check the standard potential table, i realised that can't be true... because when you sum the two half equations together, you would achieve a negative value... and from my understanding, you can't have a spontaneous reaction with a negative value right?
i was thinking that the:
Cathode : O2 + 2H2O + 4e -> 4OH-
Anode being the same as b4
please correct me if im wrong... this topic is really confusing=[
Phenolphthalein indicator turns pink in the presence of OH- ions. Consider a simple galvanic cell in which the two electrodes are zinc and iron, immersed into a saltwater electrolyte containing phenolphthalein...
a) at which electrode will the electrolyte turn pink? (i said Fe and its correct)
b)write the half-equations occurring at the cathode and anode.
so this is where i don't get, the answers says:
Cathode : 2H2O + 2e -> 2OH- + H2
Anode : Zn -> Zn2+ + 2e
when i check the standard potential table, i realised that can't be true... because when you sum the two half equations together, you would achieve a negative value... and from my understanding, you can't have a spontaneous reaction with a negative value right?
i was thinking that the:
Cathode : O2 + 2H2O + 4e -> 4OH-
Anode being the same as b4
please correct me if im wrong... this topic is really confusing=[