sharp_pencil
Member
- Joined
- Mar 8, 2009
- Messages
- 51
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- Male
- HSC
- 2009
FUCCCKCKCKKKKK i did the whole thing right except in calculation i went 0.77-0.13 I FUCKING FORGOT TO SWAP SIGN IM RAGING!!!!
how did you figure that the lead was the anode and the platinum was the cathod??
please anyone
how did you figure that the lead was the anode and the platinum was the cathod??
please anyone
i think i stuffed this up but i dont think platinum can be an electrode as it is inert... thus i sed fe2+ is anode and Pb is cathode... however due to my study of indus chem it may have been more likey for Fe3+ to undego redox bcoz it has a higher E valu... in that case it may have been Pb anode and Fe3+ cathode...anybody agree?lol, Oxidation occurs at the Anode. platinum is inert meaning it doesn't oxidise or reduce.
look at the standard potentials table, Pb -> Pb2+ + 2e-
oxidation is loss. therefore the anode was lead.
I had a similar answer to you.....but I don't know anymore. lol.i think i stuffed this up but i dont think platinum can be an electrode as it is inert... thus i sed fe2+ is anode and Pb is cathode... however due to my study of indus chem it may have been more likey for Fe3+ to undego redox bcoz it has a higher E valu... in that case it may have been Pb anode and Fe3+ cathode...anybody agree?
trust me, with the shit the board of studies has been doing they could put anything in the testNo, it wasn't electrolysis. Electrolysis isn't even in the core syllabus.
i think i stuffed this up but i dont think platinum can be an electrode as it is inert... thus i sed fe2+ is anode and Pb is cathode... however due to my study of indus chem it may have been more likey for Fe3+ to undego redox bcoz it has a higher E valu... in that case it may have been Pb anode and Fe3+ cathode...anybody agree?
perhaps, but it was not electrolysis, regardless. There was no external power source.trust me, with the shit the board of studies has been doing they could put anything in the test
why was this question so hard =S
you look at the Emf table thingo, see which one reaction is higher up and thats the one that oxidises, i.e. that reaction is occurring at the anode. Isn't that the basics of galvanic cells?
yer ... its just the Fe3+/Fe2+ that is confusing ppl... wat u do for it?why was this question so hard =S
you look at the Emf table thingo, see which one reaction is higher up and thats the one that oxidises, i.e. that reaction is occurring at the anode. Isn't that the basics of galvanic cells?
Just used the equation that was there on the standard potentials. What else could you do? =Syer ... its just the Fe3+/Fe2+ that is confusing ppl... wat u do for it?
i meant did u use Fe2+ or Fe3+ as the ion that reacted?Just used the equation that was there on the standard potentials. What else could you do? =S
Just used the equation that was there on the standard potentials. What else could you do? =S
i knew i shuld hav changed it...+1 , Fe3+ has a higher reduction potential than Fe2+
so just use that.
from memory the diagram showed electron flow going >>> so in that case the Pb anode should be on the left and the Pt cathode on the right. Anode liberates electrons and the cathode absorbs them.which side is the anode left or right, the direction of electron flow on the diagram is only part really gets me confused?
remember electricity always moves from anode to cathode, hence one one on the left was teh anode and the one on the right cathodeplease which side is anode left or right on the diagram?
what you said first is correctfrom memory the diagram showed electron flow going >>> so in that case the Pb anode should be on the left and the Pt cathode on the right. Anode liberates electrons and the cathode absorbs them.
But maybe xfer was <<< can't remember lol