kaha167
Member
- Joined
- Sep 20, 2008
- Messages
- 63
- Gender
- Female
- HSC
- 2010
hey guys,
ive tried to answer this question but feel that im stuck. i can't find the focal length of the second parabola...?
parabola x^2 = 16y coordinates of the focus = S
A second parabola also has its focus at S. the vertex of this parabola is at (-2, 4)
Find the equation of the parabola:
i have gotten to:
(x - h)^2 = 4a(y-k)
(x+2)^2 = 4a(y-k)
i dont understand how to get a when they are on the same line [there is no gap between teh vertex and the focus]
thanks for the help
ive tried to answer this question but feel that im stuck. i can't find the focal length of the second parabola...?
parabola x^2 = 16y coordinates of the focus = S
A second parabola also has its focus at S. the vertex of this parabola is at (-2, 4)
Find the equation of the parabola:
i have gotten to:
(x - h)^2 = 4a(y-k)
(x+2)^2 = 4a(y-k)
i dont understand how to get a when they are on the same line [there is no gap between teh vertex and the focus]
thanks for the help