I'll assume that you mean the area between y=2, y=4, the curve and the y axis...find the area between: y = ln x, y = 2 and y = 4. the answer is 47.2 units^2.
I can get nowhere near this number..
can anyone possible help me?
Greatly appreciated.
One way of doing is noticing that y= Inx is a slanted version of y=e^x. Inverse or something like that.find the area between: y = ln x, y = 2 and y = 4. the answer is 47.2 units^2.
I can get nowhere near this number..
can anyone possible help me?
Greatly appreciated.
Ooo rearranging.I'll assume that you mean the area between y=2, y=4, the curve and the y axis...
y=lnx
e^y=x
Required area =
units^2
You can only invert it to the exponential (e) because the log is in the natural base, e, such that it is lnx. If it weren't this way (although I highly doubt you would get this), you wouldn't be able to do it.oh ok, i didn't realise/think i could invert the log to become an e
thanks very much for your help
Or you could've done Area rectangle - integral... but that'd require knowledge of integration by parts...You can only invert it to the exponential (e) because the log is in the natural base, e, such that it is lnx. If it weren't this way (although I highly doubt you would get this), you wouldn't be able to do it.