MedVision ad

Odd function question (1 Viewer)

deltasalt

New Member
Joined
Jul 23, 2010
Messages
4
Gender
Male
HSC
2009
If a function is odd f(-x)=-f(x) for all x, prove that each odd function is zero when x=0 also prove every odd polynomial is divisible by x.

can someone show me how to do this

thankyou
 

random-1006

Banned
Joined
Jun 25, 2010
Messages
988
Gender
Male
HSC
2009
If a function is odd f(-x)=-f(x) for all x, prove that each odd function is zero when x=0 also prove every odd polynomial is divisible by x.

can someone show me how to do this

thankyou

its kind of obvious, i have no idea how you would make a formal proof

edit: no wait a minute, if you want to get technical, what about y= 1/x, its odd and it isnt zero at x=0

and your hsc 2009, why are you asking?
 
Last edited:

cyl123

Member
Joined
Dec 17, 2005
Messages
95
Location
N/A
Gender
Male
HSC
2007
Provided 0 is a part of the domain of f(x)
f(0)=-f(-0)=>
f(0)=-f(0), (-0=0 obviously)
2f(0)=0
f(0)=0

This immediately implies if f(x) is an odd polynomial, 0 is a root, (x-0)=x is a factor (factor theorem), and hence f(x) is divisible by x.

To answer the f(x)=1/x question, it is a technicality not dealt with in high school but done in university, as if I define the domain of f(x) as all real numbers, then f(x)=1/x is not a function. This is because a function f(x) is has to map EVERY number in the domain to a number in the range of f(x), which in this case is all real numbers as well. Since f(0) is infinity (not a number) so then f(x)=1/x is not a function, so I cannot apply the definition of odd function to f(x)=1/x.

However, f(x)=1/x if x=/=0, while f(x)=0 if x=0 is a indeed an odd function. But again, this isn't dealt with in high school.
 

deltasalt

New Member
Joined
Jul 23, 2010
Messages
4
Gender
Male
HSC
2009
"what about y= 1/x, its odd and it isnt zero at x=0"
Thats not a polynomial

"and your hsc 2009, why are you asking?"
Someone asked me and i cant remember how to do it
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top