S sickmyducks New Member Joined May 25, 2010 Messages 24 Gender Male HSC 2011 Jan 12, 2011 #1 differentiate: loge(x-3/x+3) explanation please
H hscishard Active Member Joined Aug 4, 2009 Messages 2,033 Location study room...maybe Gender Male HSC 2011 Jan 12, 2011 #2 sickmyducks said: differentiate: loge(x-3/x+3) explanation please Click to expand... You could do it the long way, let f(x) = (x-3)/(x+3) Better way is ln(x-3)-ln(x+3) d/dx= 1/(x-3) - 1/(x+3)
sickmyducks said: differentiate: loge(x-3/x+3) explanation please Click to expand... You could do it the long way, let f(x) = (x-3)/(x+3) Better way is ln(x-3)-ln(x+3) d/dx= 1/(x-3) - 1/(x+3)
S sickmyducks New Member Joined May 25, 2010 Messages 24 Gender Male HSC 2011 Jan 12, 2011 #3 thanks man i was trying the long way and i wasnt getting it coz i was using product instead of quotient rule fml
thanks man i was trying the long way and i wasnt getting it coz i was using product instead of quotient rule fml