HSC Mathematics Marathon (1 Viewer)

[UnrealAnchovies]

zero -its an odd function

a product of an odd function (x^3) and even function (cos(3x) ) gives an odd function

:-o

Makes sense though.

 

[Bored Of Fail 2]

:-o

Makes sense though.

functions work very similar to numbers and being " positive and negative "

odd x odd = even
odd x even = odd
even x even = even

 

[UnrealAnchovies]

functions work very similar to numbers and being " positive and negative "

odd x odd = even
odd x even = odd
even x even = even

I never knew that before. Thanks a lot!

 

[Drongoski]

I never knew that before. Thanks a lot!

Hey you guys out there. If you are looking for a maths tutor and live in Bored's area, give him a go. He is not bad at all.

 

[Bored Of Fail 2]

Hey you guys out there. If you are looking for a maths tutor and live in Bored's area, give him a go. He is not bad at all.

lol , I think everyone on this site already knows about the ad , but thanks anyway ( I guess ) .

Also majority of people seeing this are 4unit students.

 

[jyu]

Evaluate

 

[Bored Of Fail 2]

Evaluate

lol its a constant function, was in this years three unit, and its odd as well , so zero again

the discontinuity at x=0 makes no difference

 

[jyu]

lol its a constant function, was in this years three unit, and its odd as well , so zero again

the discontinuity at x=0 makes no difference

you got it right

 

[Bored Of Fail 2]

or you could say it equals -pi/2 from -4/pi <=x<0 so integral there = (4/pi ) x -pi/2

but it equals pi/2 from 0<x<=4/pi so integral there = (4/pi) x pi/2

they cancel to zero

 

[Bored Of Fail 2]

you almost got it right

there is nothing wrong with the domain

 

[Bored Of Fail 2]

http://www.wolframalpha.com/input/?i=arctan(x)++++arctan(+1/x)+

areas cancel

 

[jyu]

It isn't a constant function because a constant function cannot be odd.

 

[Bored Of Fail 2]

It isn't a constant function because a constant function cannot be odd.

you knew what I meant lol

minority technicality

 

[cutemouse]

Usually we just say function f(x), we don't say the rule f(x) of the function

f(x) is the value of the function f at the point 'x'.

 

[jyu]

f(x) is the value of the function f at the point 'x'.

You are contradicting yourself.
Before you said f(x) is the rule of the function f.
Now you are saying f(x) is the value of the function f at the point 'x'.

A rule cannot be a value.

 

[jyu]

Lol, if you're going to be all smart using notation not used in the HSC then at least get it all right. f(x) isn't a function; it's a rule.

Now I am looking at an example in a book.

'Graph the function f(x)=sinx+0.01cos100x'

Another example in the same book.

'f(x)=(x^2-x-2)/(x-2)
This function is discontinuous at a=2, since f(2) is not defined.'

 

[deterministic]

http://mathworld.wolfram.com/Function.html if you want to be pedantic but in high school, no one cares.

 

[cutemouse]

You are contradicting yourself.
Before you said f(x) is the rule of the function f.
Now you are saying f(x) is the value of the function f at the point 'x'.

A rule cannot be a value.

No I'm not.

f(x)=x^2+1 is a rule for the function f.

f(x) is the value of the function f at the point 'x'.

 

[jyu]

No I'm not.

f(x)=x^2+1 is a rule for the function f.

f(x) is the value of the function f at the point 'x'.

Let me keep on reading:
...., it is common to abbreviate an expression such as "the function f defined by f(x) = x^2+x" to "the function f(x)=x^2+x".

A function f is a rule that assigns .....

 

[jyu]

Lol, if you're going to be all smart using notation not used in the HSC then at least get it all right. f(x) isn't a function; it's a rule.

Here you said f(x) is a rule. The other post you said f(x) is a value. What is it?