Sanical
SpiderAnderson
Really? 100% sure? Do you mean I can use a) flat out, without even having delta or gamma? Or do you mean using a) once I refer to my own roots like you said in your previous reply?You can use a)...
Really? 100% sure? Do you mean I can use a) flat out, without even having delta or gamma? Or do you mean using a) once I refer to my own roots like you said in your previous reply?You can use a)...
100%, unless the person that invented polynomials would come back via a time machine and change his set of notations and destroy this lonesome planet. I would do the second option it is more correct. However if your teacher lets you do the first, then I don't see why you wouldn't. It is shorter.Really? 100% sure? Do you mean I can use a) flat out, without even having delta or gamma? Or do you mean using a) once I refer to my own roots like you said in your previous reply?
Delicious humans.Yay thanks
Importantly check with your teacher. If your teacher is a migrant like mine they will only accept the use of fancy notations.Ok, so I checked Terry Lee Polynomials. Chapter 3.3 Q14, and he uses method a). So does the cambridge 4U worked solutions. So yeah, a) seems good enough
b) is something I made upWhere'd you get b) and c) from?
Yeah, I'll check.Importantly check with your teacher. If your teacher is a migrant like mine they will only accept the use of fancy notations.
That's new...
I think it has to have the 2 in front, since symmetry implies ab and ba will be included in the permutations, but then commutativity kicks in.I thought that sym. summation ran over ALL permutations of the variables?
So
Probably just a matter of conventions...it makes Muirhead's inequality look nicer .
Yeah technically so but pshhhtttt nobody really cared about it when I did that. technically it should actually be a factor of 4, coz you can permute the c^0 and d^0 as well. Like with muirhead notation, all symsums in 4 variables have 24 termsI thought that sym. summation ran over ALL permutations of the variables?
So
Probably just a matter of conventions...it makes Muirhead's inequality look nicer .
Ah yes 4, my bad.Yeah technically so but pshhhtttt nobody really cared about it when I did that. technically it should actually be a factor of 4, coz you can permute the c^0 and d^0 as well. Like with muirhead notation, all symsums in 4 variables have 24 terms
and yeah I was basing it on symmetric polynomial sum notation
random thing, you know muirhead has a geometric interpretation?Ah yes 4, my bad.
Nope, I'm not even sure how it is proven. Its just a useful sledgehammer to know.random thing, you know muirhead has a geometric interpretation?