You used this in your solution didn't you?
yeaYou used this in your solution didn't you?
Don't worry about it. We all solved it that way.
That is how you work it out.You used this in your solution didn't you?
Edit: Because I imagine that's how you would work it out.
ah oops my bad, didn't check it properly then haha
I'm suprised no one has done it after I've given some time for people. People in year 9 and 10 should seriously give the question a go. Anyways, I will spare my time to do this Q and I will be off:to revive this thread, here's a nice simple question for you guys
CorrectI'm suprised no one has done it after I've given some time for people. People in year 9 and 10 should seriously give the question a go. Anyways, I will spare my time to do this Q and I will be off:
Now, we can express an equation for equality in area size of triangle.
Now we know by pythagorean method that
 )
Saw this question when I was going through past papers for 4U.to revive this thread, here's a nice simple question for you guys
Just out of curiosity, was it exactly the same or similar?
exactly the same one, it's a snapshot from the pdf of the actual hsc paper
When you say AX^2, do you mean:
Well AX is an interval but X is just a point, so obviously (AX)^2.When you say AX^2, do you mean:
OR
Likewise, the same goes for the 7BX^2.
The question on inspection seems straight forward (given you said equilateral triangle - tells us a lot) and although I do not have school tomorrow, I have table tennis training in the morning and I need to acquire my usual sleeping patterns unfortunately. Good night and if someone sees the Q (looking at ymcaec or anyone else), please do not hesitate to solve it.
Yes, thank you. Just wanted to clarify as I'm off for bed.
Yea, exactly what carrot said lol, same goes with the 7(BX)^2
This guy is obviously going to get a 99.95 ATAR I can just see it.I'm suprised no one has done it after I've given some time for people. People in year 9 and 10 should seriously give the question a go. Anyways, I will spare my time to do this Q and I will be off:
Now, we can express an equation for equality in area size of triangle.
Now we know by pythagorean method that
woah great job. There's also a simpler method involving pythagoras loli used cos rule
we know that
^2+(2BX)^2-2BX(BX+CX)\\AX^2=BX^2+2(2BX)BX+(2BX)^2+(2BX)^2-2BX(BX+2BX)\\AX^2=BX^2+4BX^2+4BX^2+4BX^2-2BX^2-4BX^2\\AX^2=7BX^2)
