Let the integers in the ratio 1:2:3 be a,2a and 3a and let the 4th integer be b, then 11/6a + 1/b = 19/20.
Note b>1 as 1/b < 19/20, so 1/b <= 1/2, so if a>=5, then 11/6a + 1/b <= 11/30 + 1/2 < 19/20. Hence it suffices to check a=2,3,4. Luckily a=2 gives 1/b = 19/20 - 11/12 = 1/30,
Hence (2,4,6,30) is a solution set, so find the sum of the integers 2+4+6+30 = 42.
There are normally lots of ways to do these things, but normally just trying easy stuff like bounding arguments or divisibility, even just trying to encode all the information in a set of equations is enough to get the job done.