Equation of a locus help (1 Viewer)

[Redyapper]

Hi,

I'm having trouble with:
Find the equation of the locus of a point that moves so it's equidistant from the point (2,0) and the line x=6.
Not too sure when I use distance formula for this question, and what to do with the x=6.

Thanks!

 

[Redyapper]

oh I think I worked it out actually

 

[Timothy6340]

hey i got y^2= x+32 and i used the distance formula to do it is it correct ??

 

[Redyapper]

hey i got y^2= x+32 and i used the distance formula to do it is it correct ??

Yes, that's right. Out of curiosity, how do you work it out?

 

[Timothy6340]

i used the distance formula with the A(2,0) the B(6,y) and the veriable point P(x,y)
so PA^2=PB^2
(x-2)^2 + (y-0)^2=(x-6)^2 + (y-y)^2
x^2 -4x+4+Y^2=x^2-12x+36
y^2=8x+30

 

[skillstriker]

Isn't the answer y^2 = -8x + 32

 

[Timothy6340]

Isn't the answer y^2 = -8x + 32

yea it is soz hahah just woke up

 

[Redyapper]

i used the distance formula with the A(2,0) the B(6,y) and the veriable point P(x,y)
so PA^2=PB^2
(x-2)^2 + (y-0)^2=(x-6)^2 + (y-y)^2
x^2 -4x+4+Y^2=x^2-12x+36
y^2=8x+30

ah right! thanks so much!

 

[such_such]

^ yeah I got that

I think he just simplified wrong, but working out is correct