i) To find the coordinates of
A, equate the equation of the line and the parabola. So at
A (where
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),

, i.e.
(x-4)=0)
.
Since
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at
A, we can divide through by
 )
, to get

.
To find the
y-value of
A, sub. in
x = 1 into the equation of the line. So

. So
A = (1, -3).
ii) Shaded area is given by this integral:
-(x^2 - 4x))\text{ d}x)
.