Do you happen to have the answer? Just want to compare my answer with the questionCould someone please help me with q19 part a and b
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You have the book!Do you happen to have the answer? Just want to compare my answer with the question
Hey NOPE, it's a show question so there's no solutions. How did you draw the diagram? The answer is basically what you had to show. No worked solutions unfortunately.Do you happen to have the answer? Just want to compare my answer with the question
Im at work at the moment, I left the book at home.You have the book!
I had a crack at that question tonight, happy to receive any feedback from any forumites.Could someone please help me with q19 part a and b
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Could u please show working for converting AB into vertical components. I'm not sure how u did that.I had a crack at that question tonight, happy to receive any feedback from any forumites.
I thought of a basic example like a dice at the vertical distances , with the angles to the horizontal and vertical.
Knowing that each length of a cube in this case is 'x', i then converted the AB component to a vertical length (using sine). I also did the same thing for vertex, P. Because it is a 3D shape, I converted the diagonal distance, to a vertical component as well. (using cos)
Here is my diagram:
(My pencil marks show the respective vertical components)
Like I said before its a 3D shape so , how I did it was I looked at in 2 parts. I think of AB covering the lower portion of the height, and vertex P covering the upper portion of the height. (What I have done is I have highlighted the purple in this region in the upper half, the red as the lower half). By adding the 2 vertical components we are able to obtain the vertical height mentioned.How come vertical heigh equals opposite length + adjacent length
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