Prelim 2016 Maths Help Thread (1 Viewer)

[InteGrand]

Well speaking of robbing your time Leehuan, I see you here literally all the time

With your username, of course you do.

 

[eyeseeyou]

With your username, of course you do.

Walking contradiction

 

[eyeseeyou]

BTW Integrand you need an avatar, check some out: https://www.google.com.au/search?q=...ved=0ahUKEwibvYH6-Z_NAhXlJKYKHaI8CecQ_AUIBigB

https://www.google.com.au/search?q=...KHaI8CecQ_AUIBigB#tbm=isch&q=integrand+symbol

https://www.google.com.au/search?q=...HaI8CecQ_AUIBigB#tbm=isch&q=maths+and+physics

 

[Trebla]

Um...well....idk but that's my personal preference

Sketch on one graph y=f(x) and y=f^-1(x): make sure the diagrams are to scale for

f(x)=-ln (x+1)

Do you know how to sketch a log graph in the first place?

Also do you know how to find the equation of an inverse function?

Do you know the relationship between the graph of a function and a graph of its inverse?

 

[eyeseeyou]

Do those really annoying 3D trig problems ome up again in the HSC 3 unit course or 4 unit course?

 

[eyeseeyou]

Tried this inverse function and can't solve it

FInd the inverse function of 8(x-1)^3 and find the domain and range of the inverse function

Same with this one: y=5+ squareroot of (3-x)

 

[leehuan]

Bump

Do you know how to sketch a log graph in the first place?

Also do you know how to find the equation of an inverse function?

Do you know the relationship between the graph of a function and a graph of its inverse?

 

[eyeseeyou]

Bump

Can't quite remeber how to sketch a log graph

YEah you just switch the x and y around and carry yuor restriction throughout

um...yeah

 

[leehuan]

Can't quite remeber how to sketch a log graph


um...yeah

Then go back to your notes and figure it out. Or use a graphing software.


Well, what is it?

 

[eyeseeyou]

Then go back to your notes and figure it out. Or use a graphing software.


Well, what is it?

yeah I'm using desmos atm

 

[eyeseeyou]

Do those really annoying 3D trig problems ome up again in the HSC 3 unit course or 4 unit course?

Tried this inverse function and can't solve it

FInd the inverse function of 8(x-1)^3 and find the domain and range of the inverse function

Same with this one: y=5+ squareroot of (3-x)

Some1 plz answer these 2/3 Q's

 

[Trebla]

Can't quite remeber how to sketch a log graph

YEah you just switch the x and y around and carry yuor restriction throughout

um...yeah

Have you looked through your notes or textbook again to see how to sketch it?

Okay, so using that information what is the equation of the inverse function of y=-ln(x+1)?

Have you looked through your notes or textbook again to see what that important graphical relationship is?

 

[Trebla]

Some1 plz answer these 2/3 Q's

Ok lets start with y=8(x-1)³

You said earlier to swap the x and y to find the inverse function. Do you know how to do that for y=8(x-1)³?

Also do you know how to find the domain and range of that function?

 

[eyeseeyou]

Ok lets start with y=8(x-1)³

You said earlier to swap the x and y to find the inverse function. Do you know how to do that for y=8(x-1)³?

Also do you know how to find the domain and range of that function?

DW already know how to do it

SO you are given y=8(x-1)^3

Divide both sides by 8

y/8=(x-1)^3

Then you expand the RHS

Wait...I can't remeber lol

Wait...

Switch x and y around and now its x/8=(y-1)^3

Then you cube root both sides and its: ______________

Then y=________________ +1

 

[Trebla]

DW already know how to do it

SO you are given y=8(x-1)^3

Divide both sides by 8

y/8=(x-1)^3

Then you expand the RHS

Wait...I can't remeber lol

The fact that you don't know how to make x the subject and want to do 4U is a little concerning

 

[eyeseeyou]

DW already know how to do it

SO you are given y=8(x-1)^3

Divide both sides by 8

y/8=(x-1)^3

Then you expand the RHS

Wait...I can't remeber lol

Wait...

Switch x and y around and now its x/8=(y-1)^3

Then you cube root both sides and its: ______________

Then y=________________ +1

Read this

 

[Trebla]

Read this

Ok now do you know how to find the domain and range of the original function?

 

[eyeseeyou]

Ok now do you know how to find the domain and range of the original function?

Yes, took me a while lol

 

[Trebla]

Yes, took me a while lol

Ok now do you know how to find the domain and range of the inverse?

 

[eyeseeyou]

Ok now do you know how to find the domain and range of the inverse?

Yes

Do you think I'm now ready for 4U?