Shadia has invented a game for one person. she throws two dice repeatedly until the sum of the two numbers shown is either six or eight. if the sum is six, she wins. if the sum is eight, she loses. if the sum is any other number, she continues to throw until the sum is six or eight. calculate the probability that Shadia wins the gameHey
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Probability question please help (1 Viewer)
- Thread starter kpad5991
- Start date
The solution in the book is 1/2??Firstly Integrand....... 4 AM mafffsss
pls ignore thr higlights.
Anyway.
} = \bigg(\frac{25}{36} \bigg) \bigg(\frac{5}{36} \bigg) = \bigg(\frac{125}{1296} \bigg))
} = \bigg(\frac{25}{36} \bigg)\bigg(\frac{25}{36} \bigg) \bigg(\frac{5}{36} \bigg) = \bigg(\frac{3125}{56656} \bigg) )
}{1-\bigg(\frac{25}{36}\bigg)} = \frac{5}{11} )
Okay I figured it out. Shadia continues for 26/36
kawaiipotato
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Just a note that you should expect 1/2 because the number of desired outcomes are equal in both cases.
KAIO7
Member
You've made a silly mistake in evaluating the probability of continuing the game; it should be 26/36 instead of 25/36. When using this, the limiting sum will be equal to 1/2, hence the probability of winning the game is 1/2
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