L lmao1010 Member Joined Feb 3, 2022 Messages 63 Gender Male HSC 2022 Jun 7, 2022 #1 i tried u=root e2x-1 but it doesnt seem to work thanks in advance
Lith_30 o_o Joined Jun 27, 2021 Messages 158 Location somewhere Gender Male HSC 2022 Uni Grad 2025 Jun 7, 2022 #2 multiply top and bottom by then you can integrate it either using the substitution or just directly by inverse trig integration.
multiply top and bottom by then you can integrate it either using the substitution or just directly by inverse trig integration.
L lmao1010 Member Joined Feb 3, 2022 Messages 63 Gender Male HSC 2022 Jun 8, 2022 #3 Lith_30 said: multiply top and bottom by then you can integrate it either using the substitution or just directly by inverse trig integration. Click to expand... Thanks bro
Lith_30 said: multiply top and bottom by then you can integrate it either using the substitution or just directly by inverse trig integration. Click to expand... Thanks bro
S stupid_girl Active Member Joined Dec 6, 2009 Messages 221 Gender Undisclosed HSC N/A Jun 8, 2022 #4 Let u=sqrt(e^(2x)-1) x=(1/2)ln(u^2+1) dx=u/(u^2+1) du
V vivekjain0908 New Member Joined Mar 15, 2022 Messages 23 Gender Undisclosed HSC 2022 Jun 8, 2022 #5 stupid_girl said: Let u=sqrt(e^(2x)-1) x=(1/2)ln(u^2+1) dx=u/(u^2+1) du Click to expand... aight thanks
stupid_girl said: Let u=sqrt(e^(2x)-1) x=(1/2)ln(u^2+1) dx=u/(u^2+1) du Click to expand... aight thanks
A Akshara Patil Active Member Joined Mar 12, 2022 Messages 105 Gender Female HSC 2022 Jun 8, 2022 #6 @vivekjain0908 You seem to have a lot of accounts lmao
V vivekjain0908 New Member Joined Mar 15, 2022 Messages 23 Gender Undisclosed HSC 2022 Jun 10, 2022 #7 Akshara Patil said: @vivekjain0908 You seem to have a lot of accounts lmao Click to expand... I believe you have mistaken me for someone else
Akshara Patil said: @vivekjain0908 You seem to have a lot of accounts lmao Click to expand... I believe you have mistaken me for someone else