plug in the value of the mode into the cdf and the value will be lessView attachment 45025 yea shot nesa
plug in the value of the mode into the cdf and the value will be lessView attachment 45025 yea shot nesa
Fake smarter math ahhplug in the value of the mode into the cdf and the value will be less View attachment 45028
yeah i gave up on b as wellView attachment 45026am i cooked?i cant even do b) someone help
Yeah but well in general@C_master bluds not even doing hsc
I'm starting to become a ragebaiter wth
"You either die a hero or you live long enough to become the villain"
Redemption arc starting now!!!
no bc why was i like never taught to do that??yeah i gave up on b as well
m cannot be -4 because it would lie parallel with the second line on the absolute value graph i.e. one intersectionView attachment 45026am i cooked?i cant even do b) someone help
Well y=mx passes through (0,0) hence its gradient m would need to sit in a range where the line cuts under (6,7) but also never becomes parallel with or has a greater negative gradient than the (6,7) to (9,-5) section of the line.View attachment 45026am i cooked?i cant even do b) someone help
bro they better not be an annunities question or probability question or optimization question (please)
they were nice with english so idku reckon theyll be nice this yr
We need more nice people so yeah possibly mayhaps dont??! Just give intergration and calculusu reckon theyll be nice this yr
100% annuties no doubtbro they better not be an annunities question or probability question or optimization question (please)
why cant they do themselves i cant take it anymore problems100% annuties no doubt
Annuities is shared content with standard how yall struggling with thiswhy cant they do themselves i cant take it anymore problems