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It's not necessary however it wont hurt to know it still

Oops sorry wrong way round but thank you

Yes but since 2 moles of HCl are used for 1 mole of Ba(OH)2, then the limiting agent will be not 0.005 moles of HCl but 2x0.005=0.01 moles of HCl

yep basically :D

My belief is when their decomposition is dissociation regardless

because when HCl ionises only one hydrogen ion is produced, but when Ba(OH)2 ionises 2 hydroxide ions are produced. Not sure if that will answer your question, let me know if it doesn't

When it is molten the NaCl dissociates because it is an ionic compound and the only molecules present are Na+ and Cl-, so when we pass a current through the electrolysis of these ions will occur. Note that ionise is for covalent molecules decomposing in water will dissociate is ionic compounds...

Actually you are correct when you say they will get the mark as it is written in conquering chem Butanoate and butyrate somewhere else, and essential they are the same

Hope you get feel better :D lol on my break I go on BOS and help people while watch a little part of a movie then go back

Lol aiight

Lol it's quite simple to start a new thread but anyway. As the curve will be linear or close to it, we can say \frac{[Cu^{2+}]}{0.500}=\frac{10 ppm}{0.400} \therefore Cu^{2+}=12.5 ppm which equals 12.5 mg/L therefore Cu2+ in 100 mL is 1/10x12.5=1.25 mg number of moles of Cu2+= 0.00125/65.55 =...

Sorry I have the answers but I am unable to post them until later tonight

sorry what is butanoate??

yep well done :D

It's always best to work with moles because equations are done with molar ratios, and with polymerisation of glucose the hydroxyl of the end of one and the hydrogen ion of the other glucose which it will join are removed this produces the water, the end glucose will keep the hydroxl and the...

Lol thanks but I am not that smart

You need to know how to write them and how some reactions occur

First you find the concentrations in mol/L for both Ca2+ and Mg2+, then you convert the result into milligrams of CaCO3 per litre.

Yeh just try know what how the location also affects these levels, so near a sewage plant there would be an increase in BOD and therefore a decrease in DO. Have a look at question 12 of the multiply choice in the 2008 hsc paper.

It decays into Tellerium-123 producing beta and gamma radiation. _{53}^{123}\textrm{I}\rightarrow _{52}^{123}\textrm{Te}+_{1}^{0}\textrm{e}+\gamma