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Lol so u reckon 0/5 for me? I also talked about AAS being used to analyse water samples for presence of heavy metal cations... maybe shud get something for that. P.S. Do u mean WOW, as in I totally didn't answer the question, or the other way?

Lol I bs'd it too. One point I looked at was the volume of the water body as a whole. Chlorination would be a much more effective way of treating the water for microorganisms, than something like reverse osmosis - due to high costs yadda yadda. Then my 2nd point related to any industrial...

This is what I remember. Using TWO examples, describe how features of your local? catchment area determines the way in which water is treated to a safe standard.

90/100 raw and chem WON'T count?! :eek:

Nah I did critically evaluate it. If you look at critically evaluate keywords on BOS Site, you need to look deeply at the issues/processes involved, to make a more comprehensive judgement. Thats the difference between evaluate and then critically evaluate, I think. Meh, even with 4/5 for...

In the 90s, hopefully.

the concentration was in mg/L , not mol/L

This.

12 was A. With the one about determining w/w% of the sulfate.. i got 36.6% so answer was B. Caculating the pH was B, 2.70

Well with the one for fuels, you should use scientific notation. Like, for the energy released by petrol, I put 2.6 x 106 kJ (2.s.f.)

Looking at comments from others, saying they didn't find it that easy... perhaps around 83-84/100

Acid hydrolysis of cellulose Fermentation of glucose to produce ethanol Combustion of Ethanol

Yeah, actually the one I wrote up before ( the galvanic cell equation) was a typo.. the Cl- are on the right, because the chlorine gas is reduced. :)

The equilibrium constant for that reaction was 26, and then when I determined the K-constant with the quantities they provided (because it was in moles, you had to divide by the 5.00L of gas for each gas, to get concentration) and found K (for those quantities) to be like 16.23... So I said...

because the concentration was 1.6mg/L And the sample was 100mL, you had to multiply 1.6 by 0.100L to get 0.16mg

*sigh of relief* Which parts did people find the hardest?

What was the last question again? I forgot what I put down for last one...

For people doing industrial, did you determine that the system was NOT at equilibrium?

Awesome, got this too :D And the equation was : Ni(s) + 2Cl-(aq) ----> Ni2+(aq) + Cl2(g) ?

What did you think of short answer section? I reckon it was pretty good this year. They could've made the ethanol one 7 marks instead of 5, but hey, im not complaining. The way the put the water purifying question in there was a little different - asessing catchment area features, smart move...