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will try to answer this question after thursday

all trig functions are periodic, so their values repeat after 2pi. therefore the value for 0 is equal to the value for 2pi so they are both solutions within the given domain. also, tan(pi)=tan(0)=0, you just forgot one solution for that

the x values cancelled, so there were no variable terms. So I just had a relation between a and b.... NVM fml, I neglected the denominator fack!

when i did it originally, i differentiated and found the values of a and b when to make the derivative have a value of 0. and then i subbed into the initial function to find c. why did this not work?

oh shit i see now lol. Just make the brackets a pertect square and factorise to cancel to 0

considering the planning, size, number etc. I don't think there is any way that this could not be successful

btw fus, what is the actual answer to this?

+1

Re: HSC 2012 Marathon :) -1/32. Does anyone have an answer to the one above?

this question is very much within the syllabus. It is just a general application of theory on cubic functions. There was an Ext 1 q7 a couple of years back which was similar to this

there was a question a while back posted by seanieg89 i think, and you derived the parametric equations of sin@ and cos@ if i remember correctly

great rates and marks! good luck

my sol isnt an inequality, but when b=a^2/4 and when c=a/2, the function will have infinite roots. therefore, for b>0, all real a, and all real c, the function CAN have unlimited roots. again, no idea if it is correct.

strong english/10

abc,4,4,2. there may be others...

sounds right!

where do you get all these questions from!? i want one

yeh i just put it in my calc and it wasnt

sorry, didnt read the rest of your reasining

for a triangle to be formed with the positive x axis, and the positive y axis, the gradient has to be negative does it not? if fus is assuming the point at the origin is a degenerate triangle, that is not really inclusive of the line anyways