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99.9 ATAR, no strings attached

lol at the fact that being from a place 1:20 from sydney (where i live) is classified as "disadvantaged" and "rural" AAA is quality shit. Can u defer it a year? sorry OP for hijacking thread :)

btw, how did u get to the scholarships lunch?

lol

well those two statements are mutually exclusive, so nobody gets the scholarship

the person who gets 99.85 and doesn't get any other scholarship would be a bit devo

scientia scholarship to UNSW 99.9 or high achievers scholarship to USyd 99.95. dare to dream :D

for 9a, i forgot to put an extra x0.85 in. for 11a i forgot to put a x2 in.

sorry, it is a term only used in 3u mathematics, umm basically 3C1=3, 3C2=3, 3C3=1.

<a href="http://www.codecogs.com/eqnedit.php?latex=let~t=m\\ y=mx@plus;b\\ line~passes~through~point~(-1,0)\\ m=b\\ y=m(1@plus;x)\\ sub~into~equation~of~circle\\ x^2@plus;m^2(1@plus;x)^2=1\\ making~x~the~subject\\ x^2@plus;m^2x^2@plus;2m^2x=1-m^2\\...

The furthest we learn about roots of multiplicity in the HSC syllabusses is that if the power is even, the curve will bounce, and if it is odd the curve will have a horizontal inflection point. I have always wondered, as far as having multiple roots at that point on the graph, what else is...

hmmm interesting. Why would they ask a question about it then? wolfram alpha didnt even want to do the steps for me. It said its unavailable for some reason. But thats pretty cool how you found it by trial and error.

thats fine, ill find a way!

does this work? i can't get it to go

same. and im on a school trip for the first week anyways kekekeke

yeh, MIF textbook is where that question comes from. I'll let carrot do the question for you anyway

i see you use margaret grove :)

Ill just leave them in unsimplified form. 7a) 0.3x0.7x2 b) 0.3x0.3 c) 0.7x0.7 - to check if your correct, all 3 of these answers should sum to 1 because it checks all possibilities of the sample space. 9.a)3C2x0.85x0.15 b)0.15x0.15x0.15 c) 3C1x0.15x0.15x0.85+3C2x0.15x0.85x0.85+3C3x0.85x0.85x0.85...

its supposed to be a 4, do the division and you get -4 as the remainder

his working is correct