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Syllabus areas where students displayed strength of understanding and competence in the application of skills will be highlighted. Areas where students experienced lack of knowledge, skills and understanding will also be discussed. Participants will be given advice about strategies that...

Yes it was Wellisch. (Changed his surname to Wellish in 1920, but in 1916 it was still Wellisch) Zeleny joined Yale in 1915.

Correct for #1-#6. Another hint for #7 In 1911 he was appointed assistant professor of physics at Yale University

Now I have a harder question for you relating to the 1916 Leaving Certificate examination. Who were the 7 members of the Examination Committee in 1916? To make it easier, I have listed the following 7 hints. 1. Who is the mathematics building at Sydney University named after? 2. Who was the...

Well it's more about having the correct number of solutions and ones that satisfy the original equation. With trigonometric solutions there are many ways to express the solutions. Sometimes the domain will also play a part. In this case you could use 8θ=nπ for integers n. But which integers you...

As you can see there are 6 distinct roots and none repeated. 0 is not one of those roots. However you express the trigonometric solutions, they have to be distinct and none repeated. 2 of your solutions, 2sin(3π/8) and 2sin(5π/8) are the same 2sin(π/2) = 2 is also not one of the solutions...

0 is a solution to 16x5-20x3+5x=0 but not to 16x4-20x2+5=0 cos(π/2) = 0 came about as a solution to 16x5-20x3+5x=0 Whether you express 0 as cos(π/2), cos(3π/2), etc., doesn't matter. They all have to be excluded as solutions to 16x4-20x2+5=0.

HSC Feedback Day 2023 for 2022 HSC exams presented by senior markers If you want feedback on the 2022 HSC exams from senior markers, they will be presenting it at 9am in the UTS Guthrie Theatre Building 6, 702 Harris Street, Ultimo on Feb 25, 2023.

That’s a bit of a stretch. That 115 year old is in Spain. The oldest Australian is 111 from Queensland, not NSW. And the oldest person in NSW is 109. So the more you look at it the more unlikely it is that anyone alive today did the 1916 LC. Maybe we should refocus back to the maths. So for...

I solved Question 5. First, simplify the question. wlog let S=(0,a), L=(2a,a), A=(0,0), X=(0,-a) then it has equation x^2=4ay rtp AN=NX i.e., N=(0,-a/2) For the new parabola, vertex=(0,-a), focus=(0,a), focal length=2a Then the equation is y=x^2/(4(2a))-a, so x^2=8a(y+a), directrix y=-3a...

They wouldn't have done the HSC in 1916. The first HSC was in 1967. If they did the LC in 1916, they would have been born at about 1900 making them about 123 years old. The oldest person alive today is 115. So you are posting for dead people hoping they will respond here?

Looks like a cambridge question.

I think it is that way for the website. But I used the app on my ipad and that doesn't require a subscription. Anyway I googled the proof of the formula itself and found this: Again googling was quicker than typing it up myself.

You can use the wolframalpha app with the show steps function and I get this for part a: Quicker than typing it up myself. So it's just repeated use of the reduction formula except for the last few steps. Similar thing for part b and then the answer is (ln4-1)/4. See if you can do it and...