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question 8 was all pretty basic 2unit question 9a was basic, b was decent and yes q10 was difficult

i got 0.375 for part b the area was a rectangle across the unit square wasn't it with corners, (0,1/4), (1/4,0), (3/4,1), (1, 3/4) soo, the sides are sqrt(1/8) and sqrt(1 1/8), multiplying base * height = 0.375 so P(they meet) = 0.375/1

10a ii) and iii) was too hard 10b iii) was too hard so basically 6 marks for me goodie

i got 12 minutes for the last answer which i'm 100% sure is wrong because the probability was 0.375 for 15 minutes, so for 0.5 it has to be > 15. i hope i get some marks along the way though...

the exam was difficult but do-able couldn't do 4 marks worth of questions and i'm sure i got another 4~7 marks wrong then minus the usual mistakes =.=

that is extension-1 work and it won't be required for the upcoming exam if m1 and 2 are the gradients of the two lines, then tan@ = |m1 - m2|/(1 + m1m2)

if the answer is exactly 0, then rounding to 3 significant figures is 0.00 if it is 0.00012345 then 3 sig fig would be 0.000123

0.00 has 3 significant figures

well i've never heard of this before but: P(1st) = 1/200 * $100 = 50c P(2nd) = 1/199 * $50 approx = 25c soo, 75c is her "financial expectation" but she spent 1 dollar so she loses 25c

x = 2x? lol what the? this would require extension1 knowledge Question: Solve sin22x + cos2x = 1 for 0 <= x <= pi

um 73/120 (60.8%) in 2003 scaled or aligned or whatever to an 82% last year a 111/120 would have placed you in top20 of state 100/120 is well into band 6

Question 10 Find INT.{0 to 1} x*Sqrt(1 - x)dx using the substitution x = 1 - u2

no i found the length of the arc

yes i didn't read the question... Question: Find the sum of the first 100 multiples of 5.

you press the degrees minutes seconds button [o' "] <-- assuming you have a casio calc remember your trig ratios for q1 tan30 = 120/(x + BC) tan50 = 120/BC BC = 120/tan50 1/sqrt(3) = 120tan50/(xtan50 + 120) xtan50 + 120 = 120*sqrt(3)*tan50 x = (120*sqrt(3)*tan50 -...

well you said yourself the quarterly rate was 6% so you just leave it at 6% if it says 6% p.a. (per annum) then you divide by 4

remember:- 1. "ratio of intercepts on transversals passing parallel lines are equal" 2. volume of cone = 1/3 pi r2 h 3. add interest before subtracting the monthly/yearly payment in loan repayments 4. similar triangles are your friends 5. know your graphs of secx cotx and cosecx...

yeah but not in this case however 2nd derivative will take very long and is very prone to error but then again i'm pretty crap at differentiation...

when proving a point is a maximum is the table enough? sometimes you just know that it's going to be a max so if you found a max at x = 3, will just writing f'(3 - a) > 0, f'(3) = 0, f'(3 + a) < 0 get you full marks for the proving? because sometimes there's 50 other variables and...

what is that? example?