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  1. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon wow your questions are so amazing, i cant solve that teach me please, teach me your ways sy
  2. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon ohh theres the answer how gay is that maths just turned into a guessing game
  3. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon so many options :D so say for instance we change the limits to pi/3 to p/2 the area wouldnt be infinite but is there anyway the function can be differentiated using 2U or 3U even?
  4. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon $i posted this because i didnt know how to integrate it, all i know is $\ \ cosecx = \sqrt{1+cot^2 (x)}$ which isnt even close$
  5. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon idk what im talking about lol this was the pattern i saw in solutions
  6. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon because you look at 6y and you need y^2 +6y +c to be a perfect square and only 9 makes it so so add 9 to both sides since genral equation of a circle is (x-h)^2 +(y-k)^2 = r
  7. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon \int_0^\frac{\pi}{2} \frac{1}{sin(x)} dx
  8. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon c $working out$ \ \ x^2 +y^2 +6y +9 =16\ \ x^2 +(y+3)^2=4^2 \ \ therefore\ \ center (0,-3) radius 4
  9. mahmoudali

    allnighter for legal studies

    good luck to all who do legal, and don't stress :)
  10. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon y= 3cos(2x+\frac{\pi}{4}) \frac{dy}{dx} = -6sin(2x+\frac{\pi}{4}) \frac{d^2y}{dx^2} =-12cos(2x+\frac{\pi}{4}) =0 $then solve$
  11. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon and if you dont have time leave it? :D
  12. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon if a question like this came in HSC i'd expect more than half the state not to test
  13. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon yeah FrostKruncher explained it to me and i forgot how to prove newtons method :D
  14. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon realise put the solution up for this, i cant take it anymore =(
  15. mahmoudali

    HELP WITH TRIG tan3x

    question says using \ \ sin(3x)\ \ and\ \ cos(3x)
  16. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon prove: \frac{cos(2x)}{cos(x)} = \frac{1-tan^2(x)}{sec(x)}
  17. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon \sin^2 1^{\circ}+ \sin^2 89^{\circ} =1 + .... +\sin^2 44^{\circ}+ \sin^2 46^{\circ}= 44 $your left with$ \ \ sin^2 45^{\circ}+ \sin^2 90^{\circ}= 1+\frac{1}{2}} therefore \ \ 44 + 1+\frac{1}{2}= 45 + \frac{1}{2}} Edit: sin^2 45^{\circ} \ \ is\ \ \frac{1}{2}\ \ $so...
  18. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon is your avatar a duck or an old guy with a cap i cant tell and its fucking with my mind
  19. mahmoudali

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon dont listen to sia he sucks at maths :$
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