2024 HSC Chat (5 Viewers)

[spiderfan44]

The Guy Who Created Controversial Image That Appeared In A HSC English Exam Has Spoken Out

Redditors tracked down the original source of the image that caused mass controversy among Year 12 students when it appeared in a HSC exam last week.

www.pedestrian.tv

it's been confirmed

i didnt notice it was ai when i was in the exam tbh. i saw a lot of people complaining on reddit bcuz ai doesnt use visual technique and how can you analyse something not made by a human, but its a 6 mark compare question it really wasnt that hard to identify the techniques of the image. i think the actual issue is that its stealing from other artists and photographers. its going to be a weird legal issue where i highly doubt nesa will show the image when the paper gets uploaded to nesas site just to avoid lawsuits

 

[katiekms]

people are overthinking it...it's C because you can count the median on each graph (which is at place 8.5 on all 4 - all total to 16), but on C there is nothing for where the median is supposed to be. so it just doesn't work irrespective of the box plot

I don’t think that’s how that works. Since there’s no value you just average the 8th and 9th value, that’s how medians work. i made box plots for C and D, and D is different. I already said that the five number summaries are all the same except for D, how can that be argued against when it directly affects the box plot?

 

[spiderfan44]

year 11 went really fast but year 12 has felt pretty slow

 

[vajayjay]

Exactly. 15 is C (8 in advanced). The people who selected D honestly deserved to get it wrong for trying to be a "smartass". Like I'm pretty sure question 15 (question 8 for advanced) is an iq question. If you got that wrong, your iq is definitely below 100 (no offense). IQ questions normally ask you to find the odd one out just like this. I hope NESA doesn't award the people who selected D, it's clearly possible the boxplot can look like that. Legit I just spent 30 minutes making data sets based of this and I could literally sketch a full fledged normally distributed box and whisker plot.
View attachment 45221

Being so loud and wrong is hilarious.

 

[ihatehsc24]

I don’t think that’s how that works. Since there’s no value you just average the 8th and 9th value, that’s how medians work. i made box plots for C and D, and D is different. I already said that the five number summaries are all the same except for D, how can that be argued against when it directly affects the box plot?View attachment 45240View attachment 45241

NESA making us invest so much time for 1 mcq smh

 

[radioheadfan42]

UPDATE! I underestimated my ability to recall information for modern…i have no idea if I was just absolutely having a BRAIN BLAST during trials, because I did a lot less study but finished all the questions on the paper no worries. Man.

I have been humbled. Stalin, you grey blur you…

I did not get to apartheid IM SORRY APARTHEID!!

clearly, I'm expecting my band 6 in the mail

 

[Legendary16]

Being so loud and wrong is hilarious.

The life of a troll

 

[mysterymarkmachine]

I don’t think that’s how that works. Since there’s no value you just average the 8th and 9th value, that’s how medians work. i made box plots for C and D, and D is different. I already said that the five number summaries are all the same except for D, how can that be argued against when it directly affects the box plot?View attachment 45240View attachment 45241

yes, the average of the 8th and 9th value is 8.5. therefore the median is in the 8.5th place for all graphs. using this logic you can figure out the median for A,B,D which is in the middle column and is symmetrical(like the box plot). but if this is used for C, then the median would be 0 because the 8.5th place is nothing. which is wrong

 

[katiekms]

yes, the average of the 8th and 9th value is 8.5. therefore the median is in the 8.5th place for all graphs. using this logic you can figure out the median for A,B,D which is in the middle column and is symmetrical(like the box plot). but if this is used for C, then the median would be 0 because the 8.5th place is nothing. which is wrong

once again, that’s not how that works. you just skip to the next data point. the same idea goes for a stem and leaf plot, just because theres values in the 10s place and values in the 30s place and no values in the 20s place doesn’t mean the median is 0. i don’t think you understand how this graph works.

 

[katiekms]

 

[mysterymarkmachine]

once again, that’s not how that works. you just skip to the next data point. the same idea goes for a stem and leaf plot, just because theres values in the 10s place and values in the 30s place and no values in the 20s place doesn’t mean the median is 0. i don’t think you understand how this graph works.

Yes...you skip to the next data point. then there are 7 values to the right and 8 to the left of the median. that means that the data is no longer symmetrical. that means that it cannot be matched with a symmetrical box plot. that means I don't think you understand how this graph works

 

[TheLastHope]

year 11 went really fast but year 12 has felt pretty slow

Both went quick fr

 

[katiekms]

Yes...you skip to the next data point. then there are 7 values to the right and 8 to the left of the median. that means that the data is no longer symmetrical. that means that it cannot be matched with a symmetrical box plot. that means I don't think you understand how this graph works

no? i will represent the median with a line: 1 1 2 2 2 2 3 3 | 5 5 6 6 6 6 7 7. you see how there are 8 values on either side?

 

[katiekms]

this is stuff you learn in year 7 or something i’m not even trying to be rude

 

[mysterymarkmachine]

this is stuff you learn in year 7 or something i’m not even trying to be rude

hahah these little jabs are just gonna make you feel like more stupid when you realise why it's C. HISTOGRAM = frequency of something. you've just assumed that the x axis is numbers when it may not be. it could be absolutely anything. e.g. if your "4" actually represents "amount of people in denial about question 15", then how can it be the median if no one is? (theoretical though because clearly someone is). on a histogram you can't make something that literally does not exist the median

 

[bcv]

we are still debating this histogram question

 

[radagastthebrown]

hahah these little jabs are just gonna make you feel like more stupid when you realise why it's C. HISTOGRAM = frequency of something. you've just assumed that the x axis is numbers when it may not be. it could be absolutely anything. e.g. if your "4" actually represents "amount of people in denial about question 15", then how can it be the median if no one is? (theoretical though because clearly someone is). on a histogram you can't make something that literally does not exist the median

I hope it is C because I guessed C

 

[spiderfan44]

yo i dont do m ath but based on vibes i think c

 

[ihatehsc24]

I hope it is C because I guessed C

same but looking at katie's and other solutions, all of them say D :/
plus I think katie got a valid reasoning

 

[mysterymarkmachine]

we are still debating this histogram question

i shall defend my intellectual honour to the end