Equal volumes of equimolar solutions:
H3PO4 + NaOH --> NaH2PO4(aq) + H2O
As the relative amount of OH- increases, you could get
H3PO4 + 2NaOH --> Na2HPO4(aq) + 2H2O
And with a substantial excess of NaOH, then you get
H3PO4 + 3NaOH --> Na3PO4(aq) + 3H2O
Do we need to know all three? Or just the last one.
Also, for monoprotic acids (like HCL), the concentration of it is the same as the H+ concentrations.
If you had a triprotic acid (like H3PO4), at concentration 0.1 mol/L, how do I find the H+ concetration? Is it possible?
H3PO4 + NaOH --> NaH2PO4(aq) + H2O
As the relative amount of OH- increases, you could get
H3PO4 + 2NaOH --> Na2HPO4(aq) + 2H2O
And with a substantial excess of NaOH, then you get
H3PO4 + 3NaOH --> Na3PO4(aq) + 3H2O
Do we need to know all three? Or just the last one.
Also, for monoprotic acids (like HCL), the concentration of it is the same as the H+ concentrations.
If you had a triprotic acid (like H3PO4), at concentration 0.1 mol/L, how do I find the H+ concetration? Is it possible?