MedVision ad

An integration problem (1 Viewer)

vafa

Member
Joined
Mar 16, 2006
Messages
302
Gender
Undisclosed
HSC
N/A
Find the integration of sinx(1+x^2)^(1/2) dx by using the subsituation u^2=1+cosx
 

Riviet

.
Joined
Oct 11, 2005
Messages
5,593
Gender
Undisclosed
HSC
N/A
Could you check if your question is correct and make it unambiguous? Thanks. ;)
 

vafa

Member
Joined
Mar 16, 2006
Messages
302
Gender
Undisclosed
HSC
N/A
The question is absolutely right.
 

vafa

Member
Joined
Mar 16, 2006
Messages
302
Gender
Undisclosed
HSC
N/A
this question has driven me crazy. i have been doing it since yesterday morning. i got that from my friend's book. everything seems ok except (1+x^2)^1/2

u^2=cosx+1
cosx=u^2-1
x=cos^-1(u^2-1)

and then ....
 

kimii

UltimateMEMBER :D
Joined
Mar 6, 2006
Messages
32
Gender
Female
HSC
2007
vafa said:
this question has driven me crazy. i have been doing it since yesterday morning. i got that from my friend's book. everything seems ok except (1+x^2)^1/2

u^2=cosx+1
cosx=u^2-1
x=cos^-1(u^2-1)

and then ....
but arent u trying to replace your x's with u's instead..
so making x the subject isnt right is it?

i'll do it tonite.. it might be helpful for my trials tomoro lols! i'l reply tomoro with my solution~
 

webby234

Member
Joined
Nov 14, 2005
Messages
361
Gender
Undisclosed
HSC
N/A
I'm pretty sure it isn't going to work. Using an integration calculator it says that there is no formula for the integral. Assuming, that is you are attempting to do

(1+x^2)^(1/2) Sin[x] dx
 

vafa

Member
Joined
Mar 16, 2006
Messages
302
Gender
Undisclosed
HSC
N/A
ok but then you will have
(1+(cos^-1(u^2-1))^2)^1/2 now its quite complicated and tell me how are you going to deal with that?
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top