Smeegen999
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find the acute angle between the straight lines with equations
3x - y = 5
2x - 4y + 1 = 0
thanks!!!
3x - y = 5
2x - 4y + 1 = 0
thanks!!!
me121 said:well this works by calculating the angle each line makes with zero degrees. i.e. the line horizontal from the origin.
So if you change the form,
3x - y = 5
into
y = 3x -5
i.e. gradient is 3.
and for the second one,
2x - 4y + 1 = 0
4y=2x+1
y=1/2 x + 1/4
i.e. gradient is 1/2.
Now we know that tan-1 gradient = angle the line makes with the +x axis.
so to calculate the angle between the lines we can subtract the angle of one of the lines with the angle of the other line. if this gives a negative answer, change the order of the terms. however there will always be two angles, you can calculate the other one by using 180 - angle.
this is how you would derive the formula. and as a side note, even for my hsc, i never memorised the formula, i just used the above method.
EDIT: This is a 3unit topic. You will not be examined on it in 2U. By the looks of your profile, you only do 2U.