M MathsN00b Member Joined May 27, 2015 Messages 75 Location Terra Nullius Gender Undisclosed HSC 2015 Oct 21, 2015 #1 <----link
M MathsN00b Member Joined May 27, 2015 Messages 75 Location Terra Nullius Gender Undisclosed HSC 2015 Oct 21, 2015 #3 How did you get D? I'm still lacking with molar heat combustion stuff.
H huuh New Member Joined May 20, 2015 Messages 17 Gender Male HSC 2015 Oct 21, 2015 #4 To find the mass of fuel burnt, you'll need the amount of moles i.e. n = g/molar mass To find the moles, given molar heat of combustion (2800kJ), divide the heat generated by 2800. Then multiply the moles by molar mass to get the mass.
To find the mass of fuel burnt, you'll need the amount of moles i.e. n = g/molar mass To find the moles, given molar heat of combustion (2800kJ), divide the heat generated by 2800. Then multiply the moles by molar mass to get the mass.
M MathsN00b Member Joined May 27, 2015 Messages 75 Location Terra Nullius Gender Undisclosed HSC 2015 Oct 21, 2015 #5 Is the formula for pentan-1-ol C5H11OH?
M MathsN00b Member Joined May 27, 2015 Messages 75 Location Terra Nullius Gender Undisclosed HSC 2015 Oct 21, 2015 #6 I ended up with the answer 3.7853... I think I did something wrong
H huuh New Member Joined May 20, 2015 Messages 17 Gender Male HSC 2015 Oct 21, 2015 #7 Yeah penta-1-ol is C5H11OH 108/2800 = 0.03857 moles 0.03857 x (60 + 12 x 1.008 + 16) = 3.397 or 3.40 3 sig. fig.
Yeah penta-1-ol is C5H11OH 108/2800 = 0.03857 moles 0.03857 x (60 + 12 x 1.008 + 16) = 3.397 or 3.40 3 sig. fig.
G gandalfbrah Active Member Joined Mar 22, 2015 Messages 187 Location Sanctuary Hotel Gender Undisclosed HSC 2016 Oct 22, 2015 #8 Sent from my iPhone using Tapatalk