Applications of calculus to the physical word question (1 Viewer)

[cutemouse]

Hey, can someone please do this for me?

Thanks

 

[cutemouse]

lol, can anyone help me?

 

[shuning]

回复: Re: Applications of calculus to the physical word question

ii) integrate part 1
S=5nt-S/20 t + c
when t = o
100m= c
S = 5nt - S/20t + 100m
S= ( 5nt + 100m ) / ( 1 + S/20 )

 

[shuning]

回复: Re: Applications of calculus to the physical word question

iii) the amount will be 100n

 

[random-1005]

Re: 回复: Re: Applications of calculus to the physical word question

iii) the amount will be 100n

lol answer the two easy ones
where did you get this question from, i have never seen a type of question like this before

 

[shuning]

回复: Re: Applications of calculus to the physical word question

fk i think i got em wrong T.T that's y i cant do the 1st part ......

 

[shuning]

回复: Re: 回复: Re: Applications of calculus to the physical word question

lol answer the two easy ones
where did you get this question from, if have never seen a type of question like this before

2nd part is 2 marks... 1st part is 1 mark LOL

 

[scardizzle]

Hey, can someone please do this for me?

Thanks

Im sorry but for part i) this just had to be said,

lol wut?

 

[cutemouse]

Re: 回复: Re: Applications of calculus to the physical word question

where did you get this question from

From a past trial.

 

[untouchablecuz]

given that the container is being filled at 5 L/min with saltwater of concentration n g/L
hence, it is being filled with salt at 5n g/min => so at the moment dS/dt = 5n
now, the solutions concentration IN the container is (total salt)/100L = S/100 g/L
but solution is being lost at 5 L/min => i.e. dS/dT = -(5S/100) g/min

Hence overall
dS/dt = 5n – (5S/100) = 5n – S/20

good Q