• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Area by integration question (1 Viewer)

alldaybaby

New Member
Joined
Sep 19, 2009
Messages
20
Gender
Male
HSC
2011
okay, so I know how to integrate and everything. But I am really confused about the area I am actually trying to find in this question.

Find the area enclosed btween the curve y=x^2, the x-axis and the line y= -2x + 8.

If someone could tell me the area they are looking for in this question that would be great. The answer is 6 2/3 units^2 :) Thanks heaps
 
Joined
Feb 4, 2011
Messages
145
Gender
Undisclosed
HSC
2009
intersections x^2 = -2x + 8
x^2 +2x -8 =0
(x+4)(x-2) =0

x=2, x=-4

now lets a point in the interval -4<=x<=2

say x=0

now when x=0, x^2 =0 , but -2x+8 = 8

therefore the line is above the parabola

so area = integral ( top y - bottom y ) dx between limits

= integral (-2x +8 -x^2) dx from x=2 to x=-4
 
Joined
Feb 4, 2011
Messages
145
Gender
Undisclosed
HSC
2009
the actual area is a triangle sort of thing, if you draw it up

you will see it consists of the intergal of the line and an integral of the parabola
 
Joined
Feb 4, 2011
Messages
145
Gender
Undisclosed
HSC
2009
x intercept of the line is x=4, and the intersection of the line with the parabola is x=2

and then we have a seperate area under the parabola from x=0 to x=2 ( the intersection point )

so = integral ( -2x + 8 ) dx [ 4..2] + integral (x^2) dx [ 2..0]
 
Joined
Feb 4, 2011
Messages
145
Gender
Undisclosed
HSC
2009
= [-x^2 +8x ] [ 4..2] + (x^3 /3) [ 2..0]
= ( -16 + 32) - ( -4 +16) + (8/3) - (0) = 6 2/3
 
Joined
Feb 4, 2011
Messages
145
Gender
Undisclosed
HSC
2009

lol what , I thought it was a simple top -bottom question, I couldnt be bothered drawing it at first, also what do you expect 100% undivided free help , I am listening to music and doing other stuff as well.
 

PilotMerp

Member
Joined
May 27, 2008
Messages
88
Gender
Male
HSC
2010
lol what , I thought it was a simple top -bottom question, I couldnt be bothered drawing it at first, also what do you expect 100% undivided free help , I am listening to music and doing other stuff as well.
cool down bro i was jk :p
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top