rama_v
Active Member
let x = 1sor_ju said:Can anyone please tell me how to do this question.
(1+x)^2n by expansion
prove
2nC0+2 nC1+2nC2+...+2nC2n= 4^n
the 4^n part is killinh me
how do you miraculously get 2n--> n?? this might be a really stupid question. but im stuck.><
Thank YOU!
then 22n = 4n
from first looks it seems like you should differntiate it then let x = 1
EDIT: what the hell is wrong with this BOS server lately lol, all the timings are off..Laz where r u?
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