Can I get some help with questions? (1 Viewer)

[jimmysmith560]

Where would you draw this triangle on the graph given?

It would be defined by the tangent to the curve, the x-axis (as its base) and a line you can draw from (1,1) to the x-axis (as its height), something like this:

 

[B1andB2]

How did you get the base of the triangle to be 1- r-1/r

the base of the triangle is the far right x coordinate where it ends (x=1) minus the coordinate of R which is where it starts. In part i) you proved that R has an x coordinate of r-1/r which is why it's that

 

[jimmysmith560]

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Wouldn't it be this?



Finding angle BAC will therefore require you to subtract 210° from 270°, as shown in the sample answer.

 

[jimmysmith560]

Gosh Daym jimmy, I can always count on you

Anytime my friend!

 

[jimmysmith560]

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Do you need help or have a question about this?

You need to factorise so that the and cancel each other out, meaning you'll be left with on top and on the bottom, giving you the final answer.

 

[jimmysmith560]

The end result is e^-x which then goes down to the denominator

No worries, yeah that's pretty much it!

 

[shadowlike04]

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COT is positive in the 3rd quadrant

 

[jimmysmith560]

Cos is negative in the second and third quadrants.

Cot is positive in the first and third quadrants and the region specified is 180° ≤ θ ≤ 360°, meaning you are working with the third quadrant.

 

[Life'sHard]

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How do you answer this question

"How do you answer?" You select a letter from the MC lmao.

 

[011235]

is that your working or the worked solutions working?

 

[jimmysmith560]

is that your working or the worked solutions working?

Worked solutions, he posted the same question previously if I'm not wrong.

 

[CM_Tutor]

An outlier is a score that is either more than 1.5 times the IQR above Q₃ or more than 1.5 times the IQR below Q₁. So, if there are no outliers then:

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[Life'sHard]

Thank you genius, I’m saying how do you solve for this question. How does a data set without outliers lead to this answer

Lmao happy to help hahaha.

 

[jimmysmith560]

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Would this help?

 

[quickoats]

Jimmy's response uses De Morgan's laws which you may not have been exposed to. Dr Dawn's solution is more Yr 12 appropriate

 

[Life'sHard]

You can draw a diagram for this as well with the intersection of X and Y being 0.104. X would be 0.2-0.104. Y would be 0.52-0.104. Then the thing you are solving is 1 minus everything in the venn diagram.

 

[Life'sHard]

Everything should add up to 1

 

[jimmysmith560]

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Would this help? This is y = f(x)

 

[jimmysmith560]

If you look on the image I posted. I think it has something to do with the line being on y=-3.
Since in the derivative if you sub in x, the y value would the gradient.
But we’ll have to wait for the math people to reply to this

Are you sure? A horizontal line gives a gradient of 0. You are asked to find f(6), which is relevant to the original function. Isn't this the reason you are required to integrate? Isn't the gradient determined using the original function, as seen in the graph of y = f(x) I posted?

 

[cossine]

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The m = -3 comes from graph the being f'(x).

The working weirdly set out. Not sure why they just didn't integrate from 0-6. And then equate f(6).