thats wat i did as well. but it is wrong.Think it through logically...
So we put B into the committee, that leaves 9 people and 5 spots.
Oh but, A can't be included.
So we really have 8 people and 5 spots. 8 Choose 5.
Voila!
(It'd be so awkward if I'm wrong...)
wats so funnylol.
lol yeah. i luv how he set it out like a genius and finished with a 'voila' but he failed. taeyang do u no how to do this?"(It'd be so awkward if I'm wrong...)"
fitzpatrick says it is 140. and 8C5 = 56.But surely 8C5 is right though?
The question is asking for all the committees which can be formed, but the condition is that if B is included, A must be excluded. The group can have neither A nor B, just A or just BA commitee of 6 is to be selected from a group of 10 people of which A and B are two. How many committees can be formed excluding A if B is included?
ooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhThe question is asking for all the committees which can be formed, but the condition is that if B is included, A must be excluded. The group can have neither A nor B, just A or just be.
Therefore, your solution is the total combinations, 10C6, minus all combinations where A and be are together, 8C4.
This gives an answer of 140