• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

Combinations question (1 Viewer)

MrTroll

Banned
Joined
Sep 4, 2011
Messages
43
Gender
Male
HSC
2010
A commitee of 6 is to be selected from a group of 10 people of which A and B are two. How many committees can be formed excluding A if B is included?
 

Amogh

Member
Joined
May 16, 2009
Messages
751
Gender
Undisclosed
HSC
N/A
Think it through logically...
So we put B into the committee, that leaves 9 people and 5 spots.
Oh but, A can't be included.
So we really have 8 people and 5 spots. 8 Choose 5.
Voila!

(It'd be so awkward if I'm wrong...)
 

MrTroll

Banned
Joined
Sep 4, 2011
Messages
43
Gender
Male
HSC
2010
Think it through logically...
So we put B into the committee, that leaves 9 people and 5 spots.
Oh but, A can't be included.
So we really have 8 people and 5 spots. 8 Choose 5.
Voila!

(It'd be so awkward if I'm wrong...)
thats wat i did as well. but it is wrong.
 

taeyang

Member
Joined
May 6, 2011
Messages
335
Gender
Male
HSC
2011
To be honest, I thought the answer was 8C5 as well, I dunno, 8C4 x 2 gives you 140.
 
Last edited:

tambam

Member
Joined
Dec 31, 2010
Messages
507
Gender
Female
HSC
2011
A commitee of 6 is to be selected from a group of 10 people of which A and B are two. How many committees can be formed excluding A if B is included?
The question is asking for all the committees which can be formed, but the condition is that if B is included, A must be excluded. The group can have neither A nor B, just A or just B

Therefore, your solution is the total combinations, 10C6, minus all combinations where A and B are together, 8C4.
This gives an answer of 140
 

MrTroll

Banned
Joined
Sep 4, 2011
Messages
43
Gender
Male
HSC
2010
The question is asking for all the committees which can be formed, but the condition is that if B is included, A must be excluded. The group can have neither A nor B, just A or just be.

Therefore, your solution is the total combinations, 10C6, minus all combinations where A and be are together, 8C4.
This gives an answer of 140
ooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

misread question. lol tnks.
 
U

username30

Guest
it's a really badly worded question.

You don't really know if "B must be included" or "if B is included, A must be excluded"
 
Last edited by a moderator:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top