complex numbers question! (2 Viewers)

Riviet

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Once you're familiar with the equating real and imaginary parts method, you should be able to go straight to the two equations and solving them.
 
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You can just use the formula and do it in 1 line without mucking about with equations.
 

felixcthecat

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hehe.. i feel like being surrounded by a group of math teachers ><''

riviet... by equating real and im. u get x4 - 16x2 - 15 = 0

am i rite..? so then u hav to use the quadratic equation AGAIN.. then u'd get the x2 answer, and u hav to root that before u get to the answer..

if i'm rite then i think buchanan's equation is so much faster.. but then i've also been told to remember as little equations as u can ^0^.. cuz by the end of the course i'd be too filled with equations?

edit: buchanan..u've already done ur hsc hav u? cuz i'd be soo freaked out if u havn't... =.=
 

Rax

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LOL Buchanan, nice quote
Yeah when I guess I should have looked into it a bit more then just asking about derivition. Just explaining some stuff I done lately in Ext 2 has been a bit long in its finding. thanks anyhow
 

Riviet

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felixcthecat said:
so then u hav to use the quadratic equation AGAIN.. then u'd get the x2 answer, and u hav to root that before u get to the answer...
There's no need for the quadratic formula, you can simply make a substition for x2 and in most cases you should be able to factorise by inspection unless x and y aren't integers.
 
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pLuvia

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Just stick with the equating Re and Im parts, but if you do decide to use it ask your teacher first, or use it at your own risk :)
 
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Ask them at your own risk. Most maths teachers don't know much about maths. Ha! Ha!

And I bet most of them would not be capable of proving the formula for the square roots of a complex number.

pLuvia said:
lol you might be right about that haha
Neverthless, here's the MUCH LONGER SOLUTION:



-------------------------------------------------

But wouldn't you prefer my MUCH SHORTER SOLUTION?:
 
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STx

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hmm, im thinking of using that formula in my half yearly, so it is indirectly in the syllabus?
 

Riviet

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Use at your own risk, but if you want a definite answer, ask your maths teacher and/or head of maths and see if they would approve the use of the formula.
 

Slidey

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We were told we're allowed use that formula in ANU maths courses, because it saves needlessly deriving it each time for a specific case.

I derive it each time because it's automatic and fairly swift. But there's nothing worng with using the formula. Just make sure you know how to derive it.
 

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