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Complex Numbers - Vectors (1 Viewer)

McSo

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Hi, I'm having some major problems with vectors. I've been recently trying to revise the complex numbers chapters and I've come to realise that I suck at anything vector related... I think I can do the basic things but when it comes to anything a bit more complicated I get stuck.. For example in Excercise 2.3 from the Arnold 4u Math's Book, I can only do a few questions...
The ones I can't do are:

5) On an Argnd diagram the points P and Q represent the numbers z1 and z2 respectively. OPQ is an equilateral triangle. Show that z1^2 + z2^2 = z1z2

6) Show that ||z1| - |z2|| <= |z1 + z2|. State the condition for equality to hold.

8) Show that |z1 + z2 ... + zn| <= |z1| + |z2| + ... |zn|

9) On an Argand diagram the points A and B represent the numbers z1 and z2 respectively. I is the point (1,0). D is the point such that triangle oID is similar to triangle OBA. Show that D represents z1/z2.

Can anyone help me out with those questions, and does anyone know of any good sites/resources that I could use that would make understanding these concepts easier? Thanks.
 

hyparzero

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5) If OPQ is an equilateral triangle, then |z1| = |z2| = |z1 - z2|

and just go on from there....

6) In any triangle, the sum of any two sides is always greater than the third
In the triangle OPQ;
|OP| = |z1| and |OQ| = |z2|

Let |OR| be |OP + OQ| = |z1 + z2| .... where R = z1 + z2

But |OQ| + |OQ| > |OR| and
|PQ| < |OP| + |OQ|

Thus |PQ| < |OR|

.'. ||z1| - |z2|| < |z1 + z2|

But the inequality
||z1| - |z2|| <= |z1 + z2|
will only hold true iff OPQR is a square:
ie: Arg(z1/z2) = pi/2

and so on..
 
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McSo

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hyparzero said:
5) If OPQ is an equilateral triangle, then |z1| = |z2| = |z1 - z2|

and just go on from there....

6) In any triangle, the sum of any two sides is always greater than the third
In the triangle OPQ;
|OP| = |z1| and |OQ| = |z2|

Let |OR| be |OP + OQ| = |z1 + z2| .... where R = z1 + z2

But |OQ| + |OQ| > |OR| and
|PQ| < |OQ| + |OQ|

Thus |PQ| < |OR|

.'. ||z1| - |z2|| < |z1 + z2|

But the inequality
||z1| - |z2|| <= |z1 + z2|
will only hold true iff OPQR is a square:
ie: Arg(z1/z2) = pi/2

and so on..
Thanks... But with question 5, where do I go on from there?

Oh also... whats the actual reason that |PQ| < |OQ| + |OQ| ? Like if you draw it, its obvious, but yeah...
 
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hyparzero

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McSo said:
Oh also... whats the actual reason that |PQ| < |OP| + |OQ| ? Like if you draw it, its obvious, but yeah...
|PQ| = |OQ|

therefore
|PQ| < |OP| + |OQ|
 
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echelon4

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Here's the solution for q5. It's a bit messy. Donno if there's an easier way though.....

Sorry bout the size of the picture, i donno how to scan it properly...

 
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