uh oh ... I think I got sin3x in my 3u maths trial paper and i changed it to (sin x)3 in order to solve itSoulSearcher said:cos3x
= cos x * cos2x
= cos x (1 - sin2x)
= cos x - sin2x * cos x
That can be integrated easily now.
mate there are people who dont do 4 unitSlidey said:sin^3(x) and (sinx)^3 are exactly the same thing, silly.
Another solution is integration by parts:
Int cos^3(x) dx = Int cos^2(x).(sinx)' dx
All he was doing is pointing out another way to evaluate the integral. If you're not doing extension 2, then ignore it.2syllables said:mate there are people who dont do 4 unit
wise words from a wise old man lolSoulSearcher said:All he was doing is pointing out another way to evaluate the integral. If you're not doing extension 2, then ignore it.
Shut up young'un2syllables said:wise words from a wise old man lol