HeroicPandas
Heroic!
- Joined
- Mar 8, 2012
- Messages
- 1,547
- Gender
- Male
- HSC
- 2013
if there are no limits, i'd IGNORE the absolute sign
Ugh used that to solve my question but still can't seem to get it... Here's the question I'm on, sketch the graph of √(1-cos²x) 0<x<2pi and evaluate integral when x= 3pi/2 and pi. I can sketch it but I don't know how to evaluate the integral part. Thanks heaps! .
if there are no limits, i'd IGNORE the absolute sign
No it's not just you... It appears like that for me too! But when you click 'Reply With Quote' the rest of your message appears.Is it just me or my post above is cut off and ending with "(1-cos²x) 0." rather than the whole message I wrote?
what is so hard about this, hows ur progress?Seems like the topic at the moment is the same as mine so I'll ask a question of mine here;
Find the points of intersection of the curves y=sin theta and y=cos theta for 0<pi<2pi and calculate the area between the two curves.
Is this 2 unit?Challenge Question:
Integrate square root(1 - sin2x)
Ans: sinx - cosx +c
NoIs this 2 unit?
Got it!Challenge Question:
Integrate square root(1 - sin2x)
Ans: sinx - cosx +c
lol, i think all u need to remember is Pythagorean identities (eg. sin^2 A + cos^2 A = 1)In textbooks they should at least tell me which trig identities I need to know for the 2 unit course
Oh that's easylol, i think all u need to remember is Pythagorean identities (eg. sin^2 A + cos^2 A = 1)
complementary and supplementary angles