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differentiation (1 Viewer)

sammie

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Joined
Aug 26, 2003
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23
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dungog
ok i am haing troubles with this question.
differentiate:

y=x^4(9x-1)^5

NOw i understand how to differentiatiate
like to get this

x^4.45(9x-1)^4 + (9x-1)^5.4x^3
but i don't understand how to get to

x^3(9x-1)^4(81x-4)

can someone please explain thanks.
 

chriswong

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Nov 24, 2002
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Dundas
y = x^4(9x-1)^5
dy/dx = (9x-1)^5.4x^3 + x^4(45(9x-1)^4)
= ((9x-1)^4(x^3))((36x-4)+45x)
= x^3(9x-1)^4(81x-4)
 

iambored

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Apr 27, 2003
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10,862
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HSC
2003
yeah what they said:
= x^3(9x-1)^4 (36x-4+45x)
= x^3(9x-1)^4 (81x-4)
 

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