sorry i meant n>120 not 130.yvonne_710 said:true, when n>120, then use Z...my tutor told me the same thing
What do you mean for 30<n<130? t has nothing to do with the CLT. Unless you mean use CLT to say its a Z, then estimate with t. But even then.... ???1Time4thePpl said:n<30: Assume normal distribution. Can use t statt
30<n<130: Use CLT. Say that t is a robust estimator
n>130: Use Z table. Use CLT.
so for Q11 (I), whats the answer ? E(Y) is ??? can u tell though?absolution* said:i know all the answers!
i got that one rightyvonne_710 said:so for Q11 (I), whats the answer ? E(Y) is ??? can u tell though?
a) 2*10 - 3*16 = -28myg0t said:I know im missing something very obvious.
Can someone run me through how to do Q14.
Cheers.
30,000= P( 1+0.08)^21myg0t said:Also help with question 16...
X is the causation variablepolska* said:some one just plase explain how to determine Xand Y and expalin. i dont get this
thanks heaps