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Focus and Directrices of rectangular hyperbolae (1 Viewer)

Veck

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Feb 29, 2004
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I mean the xy=c² kind
I've got no idea... I know e = root 2 for all of them
but aside from that, I'm stumped
 

googleplex

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well x^2 - y^2 = a^2 is x= +/- a/rt2
where a^2/2 = c^2

so for the xy = c^2 its just that rotated 45, therefore x + y = +/- a
 

derek_

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isn't it like S=(root(2)c,root(2)c)
S' = (-root(2)c,-root(2)c

asymptotes
y=-x+c
y=-x-c
 

paganinio

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you two have given a comprehensive answer
Foci: S(root(2)c,root(2)c) , S'(-root(2)c,-root(2)c)
Directrices: x + y = +/- a (but what does 'a' stand for?)
Asymptotes :y=-x+c, y=-x-c

I'll do them again and give you another method.
 

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