V Veck New Member Joined Feb 29, 2004 Messages 29 Oct 24, 2004 #1 I mean the xy=c² kind I've got no idea... I know e = root 2 for all of them but aside from that, I'm stumped
I mean the xy=c² kind I've got no idea... I know e = root 2 for all of them but aside from that, I'm stumped
G googleplex New Member Joined Mar 30, 2004 Messages 29 Gender Male HSC 2009 Oct 24, 2004 #2 well x^2 - y^2 = a^2 is x= +/- a/rt2 where a^2/2 = c^2 so for the xy = c^2 its just that rotated 45, therefore x + y = +/- a
well x^2 - y^2 = a^2 is x= +/- a/rt2 where a^2/2 = c^2 so for the xy = c^2 its just that rotated 45, therefore x + y = +/- a
derek_ Member Joined Aug 7, 2004 Messages 175 Location Sydney Gender Male HSC 2004 Oct 24, 2004 #3 isn't it like S=(root(2)c,root(2)c) S' = (-root(2)c,-root(2)c asymptotes y=-x+c y=-x-c
P paganinio Member Joined Sep 12, 2004 Messages 154 Location Backstreet, Smallville, Vanuatu Gender Male HSC 2006 Oct 31, 2004 #4 you two have given a comprehensive answer Foci: S(root(2)c,root(2)c) , S'(-root(2)c,-root(2)c) Directrices: x + y = +/- a (but what does 'a' stand for?) Asymptotes :y=-x+c, y=-x-c I'll do them again and give you another method.
you two have given a comprehensive answer Foci: S(root(2)c,root(2)c) , S'(-root(2)c,-root(2)c) Directrices: x + y = +/- a (but what does 'a' stand for?) Asymptotes :y=-x+c, y=-x-c I'll do them again and give you another method.