graph for projectile... (1 Viewer)

[clever angel]

how did ur graph look??? n wat wat did u's get for horizontal speed ?

 

[Inhuman]

that Q was a bit screwed up I thought.

The horizontal speed was the gradient of the graph they gave you (dx/dt=v) but I wasn't sure what to do with my own graph- it was a straight line relationship but I wasn't sure whether they wanted units or what

 

[~Dreamer]

i screwed tht q up. totally, i left it till last...my graph it was weird... i know i got it wrong

 

[Constip8edSkunk]

straight line, gradient =t

 

[ND]

I fudged that graph, i just drew a line trhough (0, 0) and (.6, 1.85) or whatever it was.

 

[Leon585]

um 2. something i think although i could be wrong which i typically am

 

[Ragerunner]

Originally posted by ND
I fudged that graph, i just drew a line trhough (0, 0) and (.6, 1.85) or whatever it was.

LOL. Same.

I had no idea.

I couldn't even do the one above that. calculate the horizontal velocity

35oiunh25y3y9859yh32q5hi8w3h2oh35#@%#!$!

 

[Takuya]

what's this?

The distance vs time graph? The speed is just the slope of the graph which was something like 1.85m/s.

The graph just looked like a bunch of straight lines of different length

 

[dnt stop runnin]

i think the answer for the first part........was simply the gradient.....that is, 1.85m/s.....u know, rise over run........not too sure but wat u rekon??......the grpah was fuked and even the question after that

 

[Belle]

LOL that question was the biggest guess ever... I just did the same as ND and drew a straight line through (6, 12).

I got 12 m/s for the horizontal speed using delta x = Uxt. It looked like projectile motion so i used that it's probably wrong though.

 

[ND]

Originally posted by Ragerunner
LOL. Same.

I had no idea.

I couldn't even do the one above that. calculate the horizontal velocity

35oiunh25y3y9859yh32q5hi8w3h2oh35#@%#!$!

I'm pretty sure we're right though.

 

[McDaddy]

Originally posted by ND
I fudged that graph, i just drew a line trhough (0, 0) and (.6, 1.85) or whatever it was.

Yeh I did the same thing, hope that's right!

 

[Inhuman]

I did the 'draw a random straight line passing through 0,0 and .6,1.85' too

I figured that since they didn't give you graph lines they didn't want it all prettified

 

[Constip8edSkunk]

it should be right....

 

[smeyo]

for the drawn graph linear with gradient as t, yeah thats what i did for the graph to with (0,0) and (0.6,1.85) which gives gradient t
for th horizontal velocity it was d/t which was the grdient 1.85

 

[Belle]

Damn, I didn't even think of using the gradient! Must have been a massive brain fart or something, that's so basic! Stupid me.

 

[ND]

Originally posted by Belle
Damn, I didn't even think of using the gradient! Must have been a massive brain fart or something, that's so basic! Stupid me.

If you drew a line through (0, 0) and (.6, 1.85), then you drew a line with gradient t.

 

[Inhuman]

I think she means the horizontal velocity. It threw me too for about a min

 

[Takuya]

The bunch of straight lines of different lengths looked stupid but they were right

I spent some time thinking about this too... Because it's horizontal velocity versus distance, and horizontal velocity is constant, i.e. flat line.

 

[Bannanafish]

er you had to plot it for different velocities