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Help please Mole Question (1 Viewer)
- Thread starter TheHoot
- Start date
adomad
HSC!!
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- Oct 10, 2008
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- HSC
- 2010
awesome. Just a note: if you can't balance an equation, then you got it wrong. since we can balance that one, we got the equation correct.
$ $ we can used the mole ratio that is given through the balanced equation Na_2S + 2AgNO_3 \to 2NaNO_3 +Ag_2 S $Hence 1:2\to 2:1.$ $\therefore moles Na_2S: moles NaNO_3 =1:2)
now we need to calculate the moles of sodium sulfide used in this reaction. if you don't understand, ask. glad to help
fine since you are off line i will just tell u the answer,
from the mole ration... mole of Na2S is 2 X0.033= 0.066 moles
using teh formula n=m/MM. we can work out the mass
now we need to calculate the moles of sodium sulfide used in this reaction. if you don't understand, ask. glad to help
fine since you are off line i will just tell u the answer,
from the mole ration... mole of Na2S is 2 X0.033= 0.066 moles
using teh formula n=m/MM. we can work out the mass
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