ordered selections = n x (n-1) x (n-2) x (n-3) x . . . for example if there are five friends... and you have to put them in places how many places could they sit?
5x4x3x2x1 = whatever the answer is.
unordered selections... where order does not matter :
= the top line is the number of objects ... only the right amount to fill up the available spaces! divided by the number of available places decreasing and timsing to zero.
eg. three students are selected out of 8 students to represent the school at a festival. how many combinations of 3 students are possible? (note order does NOT matter here.)
no of arrangements of 3 students from 8 divide by no of ways 3 students can rearrange themselves.
8x7x6 divide by 3x2x1 = calculate!
its a bit confusing hope ive made some sense.. i also hope you ppl see this b4 the exam... unlikely but it helped me revise at least!!