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^ vertical asymptote,so the highest power of x in the denominator is 1, since its just x
f(x) =[ (5/x)-1 ]/ [(4/x)-2]
then the limit is as x approaches infinity 5/x and 4/x become 0, so the asymptote will be -1/-2 = 2
no it's not thats the horizontal.... i was right except -1/-2 =/= 2 it equals half LOL^ vertical asymptote,
4-2x =/= 0
-2x =/= -4
x =/= 2
You divide by the highest power of x, then you take the limit as x approaches infinity.This may be an easy question but I just cannot understand the explanation.
Find the horizontal asymptote of these functions by dividing through by the highest power of x in the denominator.
F(x) = (5-x)/(4-2x)
Cheers