HSC 2013 MX2 Marathon (archive) (7 Viewers)

[Sy123]

Re: HSC 2013 4U Marathon

I'm going to continue 2014 on here for now

- We simply start over again, if people want to ask questions make sure to stick to Complex Numbers and maybe Polynomials firstly and then move on as time goes on

- non-2014ers are encouraged not to answer straight away initially later on we'll just slip into anyone answering like we did this year

 

[Sy123]

Re: HSC 2013 4U Marathon

 

[obliviousninja]

Re: HSC 2013 4U Marathon

I'm going to continue 2014 on here for now

- We simply start over again, if people want to ask questions make sure to stick to Complex Numbers and maybe Polynomials firstly and then move on as time goes on

- non-2014ers are encouraged not to answer straight away initially later on we'll just slip into anyone answering like we did this year

Thanks Sy for all your work throughout the year, I appreciate it. I guess I will be saying my farewells to maths now.

 

[twinklegal19]

Re: HSC 2013 4U Marathon

Is it possible to change the thread title?

 

[Kurosaki]

Re: HSC 2013 4U Marathon

Hi, for part i) is the answer supposed to be: let z= x + iy, where x and y are real, and then equating real and imaginary parts?
then we arrive at x=2at and y=at^2, which we can then rearrange to get x^2 = 4ay?

 

[Makematics]

Re: HSC 2013 4U Marathon

Is it possible to change the thread title?

good idea, i reckon it should be 2013/2014 HSC 4U Marathon
and integration marathon should also be continued

 

[twinklegal19]

Re: HSC 2013 4U Marathon

good idea, i reckon it should be 2013/2014 HSC 4U Marathon
and integration marathon should also be continued

Or just a 'HSC 4U Marathon' thread, let it last indefinitely

 

[obliviousninja]

Re: HSC 2013 4U Marathon

good idea, i reckon it should be 2013/2014 HSC 4U Marathon
and integration marathon should also be continued

i see, you are still grasping onto the idea of belonging.

 

[Sy123]

Re: HSC 2013 4U Marathon

Hi, for part i) is the answer supposed to be: let z= x + iy, where x and y are real, and then equating real and imaginary parts?
then we arrive at x=2at and y=at^2, which we can then rearrange to get x^2 = 4ay?

Yep

 

[Makematics]

Re: HSC 2013 4U Marathon

i see, you are still grasping onto the idea of belonging.

ew

imagine 2014 HSC Belonging Marathon.

The horror.

 

[obliviousninja]

Re: HSC 2013 4U Marathon

ew

imagine 2014 HSC Belonging Marathon.

The horror.

ur quote in ur sig is good. you know what makes it better? they will specify next year for mod B!!!!

 

[seanieg89]

Re: HSC 2013 4U Marathon

Qs 1 and 3 of this collection lie within complex numbers and polynomials.

 

[hit patel]

Re: HSC 2013 4U Marathon

ii) ->OZrot 45 = z cis pi/4= (2at + iat^2)(1/sqrt(2) + 1/sqrt(2)i) ????

 

[Kurosaki]

Re: HSC 2013 4U Marathon

ii) ->OZrot 45 = z cis pi/4= (2at + iat^2)(1/sqrt(2) + 1/sqrt(2)i) ????

Didn't it say clockwise not counter clockwise? (I apologise if I misunderstood the Q)

 

[hit patel]

Re: HSC 2013 4U Marathon

Didn't it say clockwise not counter clockwise? (I apologise if I misunderstood the Q)

My apologies..u understood correctly:

ii) ->OZrot -45 = z cis -pi/4= (2at + iat^2)(1/sqrt(2) - 1/sqrt(2)i) ????

 

[Sy123]

Re: HSC 2013 4U Marathon

My apologies..u understood correctly:

ii) ->OZrot -45 = z cis -pi/4= (2at + iat^2)(1/sqrt(2) - 1/sqrt(2)i) ????

Yes that is the first step, now try and find that complex number in terms of x and y, then try and find Cartesian equation

 

[SpiralFlex]

Re: HSC 2013 4U Marathon

I think it would be good if someone if bothered can compile all the questions that were posted here in a pdf and make and give it to the 2014ers in a 4U marathon 2014 thread and continue the tradition?

 

[seanieg89]

Re: HSC 2013 4U Marathon

I think it would be good if someone if bothered can compile all the questions that were posted here in a pdf and make and give it to the 2014ers in a 4U marathon 2014 thread and continue the tradition?

A few weeks ago I started making a rough compilation of all the questions I have posted on bos (mostly just random keywords that would jog my memory to the question.) Could be useful if I ever tutor or teach again.

 

[obliviousninja]

Re: HSC 2013 4U Marathon

I think it would be good if someone if bothered can compile all the questions that were posted here in a pdf and make and give it to the 2014ers in a 4U marathon 2014 thread and continue the tradition?

Thanks for volunteering Spiral. I appreciate the work.

 

[SpiralFlex]

Re: HSC 2013 4U Marathon

Thanks for volunteering Spiral. I appreciate the work.

I don't have energy/time to do that of a massive job at the moment. Perhaps you are more suited to it since you are young.