yasminee96
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- HSC
- 2013
re: HSC Physics Marathon Archive
Yeah i did this too, however when using exact values (such as t=3.61.... rather than just t=3.6) i got 63.9.
Are we supposed to use exact values or rounded throughout are workings? which is more accepted?
I'm not too sure about my answer.
Let y=0 be ground level
y=1/2 a(y)t^2 + u(y) +100
Uy=0, as it is released horizontally---> So y=1/2 a(y)t^2 + 100 (1)
x= U(x)t, Ux=10---> x=10t (2)
tan45=y/x, so y=x
Equating (1) and (2), we get a quadratic equation in terms of t---> solving I got t=3.6 and t=-5.65(t>=0, so ignore this value)
Sub t=3.6s into equation (1) we find a value for y (y= 36.5m) (how far it falls above the ground), so 100-36.5=63.5m is the distance in drops?
Sorry when I say 'y' and 'x' I mean 'delta y' and 'delta x'
Yeah i did this too, however when using exact values (such as t=3.61.... rather than just t=3.6) i got 63.9.
Are we supposed to use exact values or rounded throughout are workings? which is more accepted?
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