Dumsum
has a large Member;
Integral of (secx)^3 . tanx
Looks so simple, probably is, simple stuff is always harder though
Looks so simple, probably is, simple stuff is always harder though
I=sec³x\3+cFinalFantasy said:let I=Integral of (secx)^3 . tanx
let u=sec²x and dv\dx=secxtanx
du\dx=2sec²xtanx and v=sec x
I=sec³x-2int.sec³xtanx dx
I=sec³x-2I
therefore I=sec³x\3
*nods and smiles*...FinalFantasy said:let I=Integral of (secx)^3 . tanx
let u=sec²x and dv\dx=secxtanx
du\dx=2sec²xtanx and v=sec x
I=sec³x-2int.sec³xtanx dx
I=sec³x-2I
therefore I=sec³x\3
it's called integration by parts, there's probably other ways but i juz saw dat one so i used itDumsum said:*nods and smiles*...
We've just started Integration, is this some funky method we learn later on?
Ohh, thanks This I didn't know... :SOgden_Nash said:you could probably do it by inspection, noticing that the derivative of secx is secxtanx
∫ sec<sup>3</sup>x.tanx dxOgden_Nash said:you could probably do it by inspection, noticing that the derivative of secx is secxtanx
Haha, now that sounds very much like a Penderism.Originally posted by shafqat
its just reverse chain rule mate
what's a "Penderism"? r u referring to Bill? lolnit said:Haha, now that sounds very much like a Penderism.
I take it Bill Pender is a good teachernit said:yep, Bill Pender who I had in years 7,11 and 12
isn't Bill the head maths teacher in SGS?~ ReNcH ~ said:I take it Bill Pender is a good teacher
He's a uni professor though isn't he?